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70=0.5x^2+15x
We move all terms to the left:
70-(0.5x^2+15x)=0
We get rid of parentheses
-0.5x^2-15x+70=0
a = -0.5; b = -15; c = +70;
Δ = b2-4ac
Δ = -152-4·(-0.5)·70
Δ = 365
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{365}}{2*-0.5}=\frac{15-\sqrt{365}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{365}}{2*-0.5}=\frac{15+\sqrt{365}}{-1} $
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